On Wed, 2003-10-01 at 10:20, Brett Franck wrote: > Hi, > > I am trying to view log files using GREP and variable substitution. Let's say a > user wants to view a log file for "Sep 30" Here is the shell (BASH) script that I > put together for it. > > #!/bin/sh > cd /routerlogs > echo > date > echo > date=`date | cut -c5-7` > echo "Which Date Do You Wish to Parse?:"; read dte; > echo "Searching....." > grep -e "$date $dte" *.log | grep -e WARNING >
grep -e "$date *$dte .*WARNING" *.log should get you close this says find a line that has whatever is in $date followed by zero or more spaces followed by whatever is in $dte followed by a single space followed by zero or more of any thing followed by WARNING I think :) Bret -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED] https://www.redhat.com/mailman/listinfo/redhat-list
