Yes, That is it! Can I just make sure I understand it? the second entry in perm[ , ] indicates the column, but you are putting in a vector. This will therefore give a vector?? (any suggestions under what topic I can read about this?) So it is like a loop and each time it is filling in the next entry from TS2 and therefore choosing that column (and 100th row). A little difficult to get my head around it but it works.
Thanks a lot. onyourmark wrote: > > WOW. Is it really that compact? I will give it a try. Amazing if true. > Thanks. > > Patrick Burns wrote: >> >> You need a comma (,) not a dot (.) in your >> subscripting of the matrix. If I get the question >> correctly, you want: >> >> newTS2 <- perm[100, TS2] >> >> >> Patrick Burns >> patr...@burns-stat.com >> +44 (0)20 8525 0696 >> http://www.burns-stat.com >> (home of "The R Inferno" and "A Guide for the Unwilling S User") >> >> onyourmark wrote: >>> Hi. >>> newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... , >>> perm[100.TS2[2000]]) >>> >>> newTS2 is supposed to be a vector of 2000 values. >>> The first value is supposed come from a particular element of the matrix >>> called 'perm'. >>> >>> I thought that >>> perm[100.TS2[1]] >>> would be valid code in R to refer to that element. >>> It is meant to choose the element from 'perm' in the 100th row and in >>> the >>> column indicated by >>> TS2[1]. In other words, TS2[1] is the first element in the TS2 vector. >>> >>> For example, if the first element in the TS2 vector was 5 then I would >>> want >>> to choose the (100,5) element from perm to be the first entry in >>> newTS2. >>> >>> Does this make sense? Thanks. >>> >>> onyourmark wrote: >>> >>>> Hi. I am sure there is a better way in R to do this then using a loop >>>> but >>>> I >>>> am new to it and not sure what to do. I think it might be something >>>> about >>>> using a function as an argument but not sure. >>>> >>>> I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in >>>> Z >>>> and 0<x<8} (where Z is the set of Integers). >>>> >>>> Then I also have a 5050 x 7 matrix called 'perm' whose entries are also >>>> from >>>> the set {x: x is in Z and 0<x<8} >>>> >>>> I want to construct the following transformation of TS2 which will >>>> still >>>> be >>>> a vector of size 1 x 2000 and which I will call 'newTS2' such that: >>>> >>>> newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... , >>>> >>> >>> Perhaps you can explain what the last line is supposed to do? This is >>> invalid R code and also not a known mathematical notation for me .... >>> >>> Uwe Ligges >>> >>> >>> >>>> perm[100.TS2[2000]]) >>>> >>>> Is there a nice way to do this without a loop? >>>> >>>> Thank you. >>>> >>> >>> ______________________________________________ >>> R-help@r-project.org mailing list >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> >>> >>> >>> >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >> > > -- View this message in context: http://www.nabble.com/how-to-do-this-%22the-R-way%22-tp22864354p22881356.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
