You need a comma (,) not a dot (.) in your
subscripting of the matrix. If I get the question
correctly, you want:
newTS2 <- perm[100, TS2]
Patrick Burns
patr...@burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of "The R Inferno" and "A Guide for the Unwilling S User")
onyourmark wrote:
Hi.
newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... ,
perm[100.TS2[2000]])
newTS2 is supposed to be a vector of 2000 values.
The first value is supposed come from a particular element of the matrix
called 'perm'.
I thought that
perm[100.TS2[1]]
would be valid code in R to refer to that element.
It is meant to choose the element from 'perm' in the 100th row and in the
column indicated by
TS2[1]. In other words, TS2[1] is the first element in the TS2 vector.
For example, if the first element in the TS2 vector was 5 then I would want
to choose the (100,5) element from perm to be the first entry in
newTS2.
Does this make sense? Thanks.
onyourmark wrote:
Hi. I am sure there is a better way in R to do this then using a loop but
I
am new to it and not sure what to do. I think it might be something about
using a function as an argument but not sure.
I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in Z
and 0<x<8} (where Z is the set of Integers).
Then I also have a 5050 x 7 matrix called 'perm' whose entries are also
from
the set {x: x is in Z and 0<x<8}
I want to construct the following transformation of TS2 which will still
be
a vector of size 1 x 2000 and which I will call 'newTS2' such that:
newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... ,
Perhaps you can explain what the last line is supposed to do? This is
invalid R code and also not a known mathematical notation for me ....
Uwe Ligges
perm[100.TS2[2000]])
Is there a nice way to do this without a loop?
Thank you.
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