Hi. I am sure there is a better way in R to do this then using a loop but I am new to it and not sure what to do. I think it might be something about using a function as an argument but not sure.
I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in Z and 0<x<8} (where Z is the set of Integers). Then I also have a 5050 x 7 matrix called 'perm' whose entries are also from the set {x: x is in Z and 0<x<8} I want to construct the following transformation of TS2 which will still be a vector of size 1 x 2000 and which I will call 'newTS2' such that: newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... , perm[100.TS2[2000]]) Is there a nice way to do this without a loop? Thank you. -- View this message in context: http://www.nabble.com/how-to-do-this-%22the-R-way%22-tp22864354p22864354.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.