Wow! Amazing stuff.
It will take me a while to digest all that you have offered here.

I came up with a simple solution myself:
y<- (-1*x)+1

Thank you
_________________
Paul Zachos, PhD
Director, Research and Evaluation
Association for the Cooperative Advancement of Science and Education (ACASE)
110 Spring Street  Saratoga Springs, NY 12866  |  
p...@acase.org  |  www.acase.org




> On May 19, 2025, at 3:08 AM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
> 
> Às 18:40 de 18/05/2025, paul zachos via R-help escreveu:
>> Dear R Community
>> I am an R beginner
>> I have a vector of ‘1’s and ‘0’s
>> x
>>  [1] 0 0 1 0 0 1 1 0 1 0 1 1 1 0 1 1 0 0 1 0 1 0 1 0 0 0 0
>> [28] 0 1 1 0 1 0 1 1 0 0 0 0 1 0 1 1 0 0 1 0 0 1 0 0 0 1 1
>> [55] 0 0 1 0 1 0 0 0 1 1 1 1 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0
>> [82] 1 1 1 0 1 0 0 1 0 0 1 1 1 1 1
>> I would like to generate a new vector  in which the ‘1’s in x become ‘0’s 
>> and the ‘0’s in x become ‘1’s.
>> How should I go about this?
>> Thank you,
>> paz
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> Hello,
> 
> A simple way is to treat x as logical and negate its values. Then coerce to 
> integer.
> 
> 
> x <- c(0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 1L, 0L, 1L,
> 1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L,
> 1L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 1L, 0L,
> 0L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L,
> 1L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 0L, 0L,
> 0L, 0L, 1L, 1L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 1L, 1L,
> 1L)
> 
> 
> as.integer(!x)
> #>  [1] 1 1 0 1 1 0 0 1 0 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 1 0 0 1 0 1 0 0 
> 1 1 1
> #> [39] 1 0 1 0 0 1 1 0 1 1 0 1 1 1 0 0 1 1 0 1 0 1 1 1 0 0 0 0 1 0 1 1 1 0 1 
> 1 0 0
> #> [77] 1 1 1 1 1 0 0 0 1 0 1 1 0 1 1 0 0 0 0 0
> 
> 
> Also, the recommended way of posting data is with ?dput:
> 
> 
> dput(x)
> #> c(0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 1L, 0L, 1L,
> #> 1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L,
> #> 1L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 1L, 0L,
> #> 0L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L,
> #> 1L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 0L, 0L,
> #> 0L, 0L, 1L, 1L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 1L, 1L,
> #> 1L)
> 
> 
> Hope this helps,
> 
> Rui Barradas
> 
> 
> -- 
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