Às 18:40 de 18/05/2025, paul zachos via R-help escreveu:
Dear R Community
I am an R beginner
I have a vector of ‘1’s and ‘0’s
x
[1] 0 0 1 0 0 1 1 0 1 0 1 1 1 0 1 1 0 0 1 0 1 0 1 0 0 0 0
[28] 0 1 1 0 1 0 1 1 0 0 0 0 1 0 1 1 0 0 1 0 0 1 0 0 0 1 1
[55] 0 0 1 0 1 0 0 0 1 1 1 1 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0
[82] 1 1 1 0 1 0 0 1 0 0 1 1 1 1 1
I would like to generate a new vector in which the ‘1’s in x become ‘0’s and
the ‘0’s in x become ‘1’s.
How should I go about this?
Thank you,
paz
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Hello,
A simple way is to treat x as logical and negate its values. Then coerce
to integer.
x <- c(0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 1L, 0L, 1L,
1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L,
1L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 1L, 0L,
0L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L,
1L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 0L, 0L,
0L, 0L, 1L, 1L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 1L, 1L,
1L)
as.integer(!x)
#> [1] 1 1 0 1 1 0 0 1 0 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 1 0 0 1 0
1 0 0 1 1 1
#> [39] 1 0 1 0 0 1 1 0 1 1 0 1 1 1 0 0 1 1 0 1 0 1 1 1 0 0 0 0 1 0 1 1
1 0 1 1 0 0
#> [77] 1 1 1 1 1 0 0 0 1 0 1 1 0 1 1 0 0 0 0 0
Also, the recommended way of posting data is with ?dput:
dput(x)
#> c(0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 1L, 0L, 1L,
#> 1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L,
#> 1L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 1L, 0L,
#> 0L, 1L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L,
#> 1L, 1L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 0L, 0L, 0L,
#> 0L, 0L, 1L, 1L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 1L, 1L, 1L, 1L,
#> 1L)
Hope this helps,
Rui Barradas
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