On 08/08/13 20:27, Jim Lemon wrote:
On 08/08/2013 04:23 PM, Kevin Parent wrote:
Well that almost works, and I didn't know about duplicated() so
thanks for that. However, it only gives me the duplicated values. I
need the original ones too. So the result I want is:
[g,g,m,m,s,s,t,t,u,u,u,v,v,x,x,y,y,y]. What duplicated() gives me is
[g,m,s,t,u,u,v,x,y,y]
Hi Kevin,
How about:
x[x %in% duplicated(x)]
Uh, I think you mean
x[x %in% x[duplicated(x)]]
Another idear:
tx <- table(x)
tx <- tx[tx>1]
rep(names(tx),tx)
Well, that's three lines as opposed to one, so not as good. But it
perhaps demonstrates
a useful tool to add to one's kit.
cheers,
Rolf
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