On 08/08/2013 06:52 PM, Berend Hasselman wrote:
On 08-08-2013, at 10:27, Jim Lemon<j...@bitwrit.com.au> wrote:
On 08/08/2013 04:23 PM, Kevin Parent wrote:
Well that almost works, and I didn't know about duplicated() so thanks for
that. However, it only gives me the duplicated values. I need the original ones
too. So the result I want is: [g,g,m,m,s,s,t,t,u,u,u,v,v,x,x,y,y,y]. What
duplicated() gives me is [g,m,s,t,u,u,v,x,y,y]
Hi Kevin,
How about:
x[x %in% duplicated(x)]
Don't you mean this
x[x %in% x[duplicated(x)]]
Berend
Ah, yes, thanks.
Jim
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