Well that almost works, and I didn't know about duplicated() so thanks for
that. However, it only gives me the duplicated values. I need the original ones
too. So the result I want is: [g,g,m,m,s,s,t,t,u,u,u,v,v,x,x,y,y,y]. What
duplicated() gives me is [g,m,s,t,u,u,v,x,y,y]
Playing around with it, I got this but can't helping thinking there must be a
less awkward way:
set.seed(2013)
x<-sort(c(letters,letters[sample(26,10,1)]))
x<-x[duplicated(x)]
x<-sort(c(x,unique(x)))
_____
Kevin Parent, Ph.D
Korea Maritime University
________________________________
From: David Winsemius <dwinsem...@comcast.net>
Cc: "r-help@r-project.org" <r-help@r-project.org>
Sent: Thursday, August 8, 2013 3:03 PM
Subject: Re: [R] Extracting only multiple occurrences
On Aug 7, 2013, at 10:37 PM, Kevin Parent wrote:
> Hoping someone here can help me with this small problem.
> set.seed(2013)
>
> x<-sort(c(letters,letters[sample(26,10,1)]))
>
> This gives a vector of 36 letters with some muliples (in this case,
> g,m,s,t,u,v,x,y). Now what I need is to get rid of the ones that only occur
> once and keep the multiples. I need the opposite of the unique() function. I
> expect this should be pretty easy but I can't see it. Anyone know a solution?
> Thanks in advance!
>
>
?duplicated
x[ duplicated(x) ]
David Winsemius
Alameda, CA, USA
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