Presumably you wish to *calculate*
exp(1347) - exp(eps + 1351) where eps = ln(0.1)
(rather than *solve* anything).
This is equal to
exp(1347)*(1 - exp(eps + 4)) = - exp(1347 + log(exp(eps+4) - 1)
= -exp(1347 + 1.495107) = - exp(1348.495107)
This is, to all intents and purposes, minus infinity.
cheers,
Rolf Turner
On 02/05/2013 04:59 AM, francesca casalino wrote:
I am sorry I have confused you, the logs are all base e:
ln(a) = 1347
ln(b) = 1351
And I am trying to solve this expression:
exp( ln(a) ) - exp( ln(0.1) + ln(b) )
Thank you.
2013/2/4 francesca casalino <francy.casal...@gmail.com>:
Dear R experts,
I have the logarithms of 2 values:
log(a) = 1347
log(b) = 1351
And I am trying to solve this expression:
exp( ln(a) ) - exp( ln(0.1) + ln(b) )
But of course every time I try to exponentiate the log(a) or log(b)
values I get Inf. Are there any tricks I can use to get a real result
for exp( ln(a) ) - exp( ln(0.1) + ln(b) ), either in logarithm or
exponential form?
Thank you very much for the help
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