Hello, Use a simple transfomation. Divide both t
log.a <- 1347 log.b <- 1351 tmp1 <- exp(log.a - log(0.1) - log.b) - 1 result <- tmp1 * exp(0.1 + log.b) # -Inf Using base 10, the result would be -4.405386507*10^585 a number too large for R. See the help page ?.Machine Hope this helps, Rui Barradas Em 04-02-2013 15:11, francesca casalino escreveu:
Dear R experts, I have the logarithms of 2 values: log(a) = 1347 log(b) = 1351 And I am trying to solve this expression: exp( ln(a) ) - exp( ln(0.1) + ln(b) ) But of course every time I try to exponentiate the log(a) or log(b) values I get Inf. Are there any tricks I can use to get a real result for exp( ln(a) ) - exp( ln(0.1) + ln(b) ), either in logarithm or exponential form? Thank you very much for the help ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
