I am a noob. I am familiar with factors, but not familiar with how that
relates to "two distinct values". How were you able to tell?
Please point me out.
Mike
On Wed, Jun 20, 2012 at 9:53 PM, David Winsemius <dwinsem...@comcast.net>wrote:
> Dear Conventional Wisdom;
>
> You do realize you only have two distinct values in that factor variable,
> right?
>
> dat <- structure( c(78L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L)....
>
> -- David.
>
>
> On Jun 20, 2012, at 9:26 PM, C W wrote:
>
> Hi R list,
>> I imported values from Excel, there is a column with numbers like 45%,
>> 65%,
>> 12%.
>>
>> I want to find its mean. What should I use?
>>
>> strisplit()
>> split()
>> parse()
>>
>> Data from dput(),
>>
>> structure(c(78L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("",
>>
>> "-0.15%", "-0.34%", "-1.3%", "-10.77%", "-100.00%", "-11.45%",
>>
>> "-12.53%", "-13.06%", "-15.36%", "-15.82%", "-16.96%", "-18.71%",
>>
>> "-2.02%", "-2.94%", "-21.23%", "-25.00%", "-26.20%", "-29.79%",
>>
>> "-3.16%", "-3.67%", "-30.52%", "-33.44%", "-37.48%", "-37.89%",
>>
>> "-39.42%", "-45.88%", "-5.09%", "-51.64%", "-61.58%", "-62.87%",
>>
>> "-63.51%", "-7.00%", "-7.90%", "-8.33%", "-8.58%", "-8.88%",
>>
>> "-91.10%", "-94.08%", "-96.01%", "0.98%", "10.00%", "10.04%",
>>
>> "10.64%", "11.11%", "114.32%", "12.09%", "12.68%", "13.77%",
>>
>> "14.10%", "15.51%", "16.25%", "16.93%", "16.94%", "18.57%", "18.88%",
>>
>> "2.46%", "2.55%", "2.79%", "2.93%", "20.00%", "22.67%", "24.50%",
>>
>> "25.76%", "28.18%", "3.26%", "3.80%", "3.83%", "36.05%", "37.22%",
>>
>> "40.63%", "5.53%", "5.70%", "6.19%", "6.62%", "6.72%", "63.33%",
>>
>> "7.14%", "7.21%", "7.39%", "9.15%", "9.99%", "95.00%"), class = "factor")
>>
>> Thanks,
>>
>> Mike
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________**________________
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>>
>
> David Winsemius, MD
> West Hartford, CT
>
>
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