Hi R list, I imported values from Excel, there is a column with numbers like 45%, 65%, 12%.
I want to find its mean. What should I use? strisplit() split() parse() Data from dput(), structure(c(78L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "-0.15%", "-0.34%", "-1.3%", "-10.77%", "-100.00%", "-11.45%", "-12.53%", "-13.06%", "-15.36%", "-15.82%", "-16.96%", "-18.71%", "-2.02%", "-2.94%", "-21.23%", "-25.00%", "-26.20%", "-29.79%", "-3.16%", "-3.67%", "-30.52%", "-33.44%", "-37.48%", "-37.89%", "-39.42%", "-45.88%", "-5.09%", "-51.64%", "-61.58%", "-62.87%", "-63.51%", "-7.00%", "-7.90%", "-8.33%", "-8.58%", "-8.88%", "-91.10%", "-94.08%", "-96.01%", "0.98%", "10.00%", "10.04%", "10.64%", "11.11%", "114.32%", "12.09%", "12.68%", "13.77%", "14.10%", "15.51%", "16.25%", "16.93%", "16.94%", "18.57%", "18.88%", "2.46%", "2.55%", "2.79%", "2.93%", "20.00%", "22.67%", "24.50%", "25.76%", "28.18%", "3.26%", "3.80%", "3.83%", "36.05%", "37.22%", "40.63%", "5.53%", "5.70%", "6.19%", "6.62%", "6.72%", "63.33%", "7.14%", "7.21%", "7.39%", "9.15%", "9.99%", "95.00%"), class = "factor") Thanks, Mike [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.