Dear Conventional Wisdom;
You do realize you only have two distinct values in that factor
variable, right?
dat <- structure( c(78L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L)....
-- David.
On Jun 20, 2012, at 9:26 PM, C W wrote:
Hi R list,
I imported values from Excel, there is a column with numbers like
45%, 65%,
12%.
I want to find its mean. What should I use?
strisplit()
split()
parse()
Data from dput(),
structure(c(78L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("",
"-0.15%", "-0.34%", "-1.3%", "-10.77%", "-100.00%", "-11.45%",
"-12.53%", "-13.06%", "-15.36%", "-15.82%", "-16.96%", "-18.71%",
"-2.02%", "-2.94%", "-21.23%", "-25.00%", "-26.20%", "-29.79%",
"-3.16%", "-3.67%", "-30.52%", "-33.44%", "-37.48%", "-37.89%",
"-39.42%", "-45.88%", "-5.09%", "-51.64%", "-61.58%", "-62.87%",
"-63.51%", "-7.00%", "-7.90%", "-8.33%", "-8.58%", "-8.88%",
"-91.10%", "-94.08%", "-96.01%", "0.98%", "10.00%", "10.04%",
"10.64%", "11.11%", "114.32%", "12.09%", "12.68%", "13.77%",
"14.10%", "15.51%", "16.25%", "16.93%", "16.94%", "18.57%", "18.88%",
"2.46%", "2.55%", "2.79%", "2.93%", "20.00%", "22.67%", "24.50%",
"25.76%", "28.18%", "3.26%", "3.80%", "3.83%", "36.05%", "37.22%",
"40.63%", "5.53%", "5.70%", "6.19%", "6.62%", "6.72%", "63.33%",
"7.14%", "7.21%", "7.39%", "9.15%", "9.99%", "95.00%"), class =
"factor")
Thanks,
Mike
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