On Aug 5, 2011, at 12:21 PM, Paul Smith wrote:

On Fri, Aug 5, 2011 at 4:54 PM, David Winsemius <dwinsem...@comcast.net > wrote:
I have just estimated this model:
-----------------------------------------------------------
Logistic Regression Model

lrm(formula = Y ~ X16, x = T, y = T)

Model Likelihood Discrimination Rank Discrim.
                      Ratio Test            Indexes          Indexes

Obs 82 LR chi2 5.58 R2 0.088 C 0.607 0 46 d.f. 1 g 0.488 Dxy 0.215 1 36 Pr(> chi2) 0.0182 gr 1.629 gamma 0.589 max |deriv| 9e-11 gp 0.107 tau- a 0.107
                                        Brier    0.231

        Coef    S.E.   Wald Z Pr(>|Z|)
Intercept -1.3218 0.5627 -2.35  0.0188
X16=1      1.3535 0.6166  2.20  0.0282
-----------------------------------------------------------

Analyzing the goodness of fit:

-----------------------------------------------------------

resid(model.lrm,'gof')

Sum of squared errors     Expected value|H0                    SD
       1.890393e+01          1.890393e+01          6.073415e-16
                  Z                     P
      -8.638125e+04          0.000000e+00
-----------------------------------------------------------

From the above calculated p-value (0.000000e+00), one should discard

this model. However, there is something that is puzzling me: If the
'Expected value|H0' is so coincidental with the 'Sum of squared
errors', why should one discard the model? I am certainly missing
something.

It's hard to tell what you are missing, since you have not described your reasoning at all. So I guess what is at error is your expectation that we would have drawn all of the unstated inferences that you draw when offered the output from lrm. (I certainly did not draw the inference that "one
should discard the model".)

resid is a function designed for use with glm and lm models. Why aren't you
 using residuals.lrm?

----------------------------------------------------------
residuals.lrm(model.lrm,'gof')
Sum of squared errors     Expected value|H0                    SD
        1.890393e+01          1.890393e+01          6.073415e-16
                   Z                     P
       -8.638125e+04          0.000000e+00

Great. Now please answer the more fundamental question. Why do you think this mean "discard the model"?

David Winsemius, MD
West Hartford, CT

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