I'd suggest rewriting this expression in some easier way:
p += (*p == '%' && *(p + 1)) ? 2 : 1;
I'd prefer
if (*p == '%')
p++;
p++;
However, that could be only my taste:)
On 26 March 2013 15:10, Maksim Kuznetsov <maks.kuznet...@gmail.com> wrote:
>> Thanks for the explanation, now I understand it. I fixed the patch
>> according to your remarks. I removed %| support since we don't
>> actually need it in i386 right now, it was added for the purpose of
>> possible generalization.
>>
>> Updated patch is attached.
>
> Ping
>
> --
> Maxim Kuznetsov
--
---
Best regards,
Michael V. Zolotukhin,
Software Engineer
Intel Corporation.
