On Mon, Mar 14, 2011 at 04:03:45AM +0100, Heiko Baums wrote:
> Am Sun, 13 Mar 2011 22:58:21 -0400
> schrieb Dave Reisner <[email protected]>:
>
> > Absolutely not. ${var} is identical to $var in every way except one:
> >
> > $varfoo != ${var}foo
> >
> > The curly braces otherwise provide zero differentiation in expansion
> > rules when used in this fashion.
>
> You're wrong again. ${variable} is the same as "$variable".
>
> From `man bash`:
> ${parameter}
> The value of parameter is substituted. The braces are
> required when parameter is a positional parameter with more than one
> digit, or when parameter is followed by a character which is not to be
> interpreted as part of its name.
>
> Heiko
I don't see how that absolves you from word splitting during expansion.
Rather, it enforces the point I made about $varfoo versus ${var}foo.
Since / is not a valid character in a variable name, the var name ends
before it. How about you do a simple test?
$ var="foo bar"
$ touch ${var}
How many files were created? Remember this is bash, not ZSH.
dave
