I've had similar problems lately working with strings.
SPARQL snippets unctions that worked on other products and produced this
kind of errors in Virtuoso.
Try using:
STRDT(?literal, xsd:string)
as input to the substr() function,
and it should work.
On Tue, Nov 1, 2016 at 3:22 PM, Jindřich Mynarz <mynarzjindr...@gmail.com>
wrote:
> Hi,
>
> I have a query that first filters literals of given length:
>
> FILTER (STRLEN(?literal) = 8)
>
> And then it extracts a substring via SUBSTR():
>
> SUBSTR(?literal, 8, 1)
>
> However, Virtuoso throws Virtuoso 22011 Error SR026: SPARQL substr: Bad
> string subrange: from=8, len=1.
>
> How is that possible?
>
> I'm using the develop version of Virtuoso (https://github.com/openlink/
> virtuoso-opensource/commit/377438ac6beefa9373cf0500c7edf4077f687d0c).
>
> - Jindřich
>
> --
> Jindřich Mynarz
> http://mynarz.net/#jindrich
>
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