Hi,
I have a query that first filters literals of given length:
FILTER (STRLEN(?literal) = 8)
And then it extracts a substring via SUBSTR():
SUBSTR(?literal, 8, 1)
However, Virtuoso throws Virtuoso 22011 Error SR026: SPARQL substr: Bad
string subrange: from=8, len=1.
How is that possible?
I'm using the develop version of Virtuoso (
https://github.com/openlink/virtuoso-opensource/commit/377438ac6beefa9373cf0500c7edf4077f687d0c
).
- Jindřich
--
Jindřich Mynarz
http://mynarz.net/#jindrich
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