> Date: Sun, 22 Jan 2012 21:28:14 -0500
> From: d...@davea.name
> To: sur...@live.com
> CC: tutor@python.org
> Subject: Re: [Tutor] how to handle very large numbers
>
> On 01/22/2012 09:08 PM, Surya K wrote:
> > Well,
> > I have been doing a puzzle where I have to deal with number 10^18. A
> > variable can store that value but can't do operations.Ex: If I use range()
> > on it, it shows overflow error.
> > So, How do I handle this. I have to use range() for that number.. in this
> > instance.
> > Also mention how to handle in other cases too (A small tutorial/ book would
> > be appreciated )
> >
> > Thanks
> >
> Check out the ongoing thread of someone who's probably doing the same
> assignment. Subject is "OverflowError in lucky numbers script"
>
> Short answers for range(): You need to specify your Python version.
>
> In Python 2.7, range() has no problem handling longs as its arguments.
> It does have a problem when the number of items gets too large for
> memory. You could avoid the memory problem by using xrange(), which is
> restricted to ints. You can, however, write a generator to operate over
> a series of such longs.
>
> I don't believe Python 3.x range has any constraints, and it's already a
> generator, so you'll have to be more specific about what your
> environment is.
>
>
> --
>
> DaveA
>
I am using Python 2.7. I don't think range() can take large values.
example:
I took a = 1000000000000000000 (10^18); This is the max limit in a puzzle.
python showed the following error :OverflowError: range() has too many items.
I even tried using xrange(), I didn't solve the issue..
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