On 01/22/2012 09:08 PM, Surya K wrote:
Well,
I have been doing a puzzle where I have to deal with number 10^18. A variable
can store that value but can't do operations.Ex: If I use range() on it, it
shows overflow error.
So, How do I handle this. I have to use range() for that number.. in this
instance.
Also mention how to handle in other cases too (A small tutorial/ book would be
appreciated )
Thanks
Check out the ongoing thread of someone who's probably doing the same
assignment. Subject is "OverflowError in lucky numbers script"
Short answers for range(): You need to specify your Python version.
In Python 2.7, range() has no problem handling longs as its arguments.
It does have a problem when the number of items gets too large for
memory. You could avoid the memory problem by using xrange(), which is
restricted to ints. You can, however, write a generator to operate over
a series of such longs.
I don't believe Python 3.x range has any constraints, and it's already a
generator, so you'll have to be more specific about what your
environment is.
--
DaveA
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