On Mon, Mar 28, 2011 at 6:43 PM, Rance Hall <ran...@gmail.com> wrote:
> I had been doing this under windows: > > import os > import sys > > osname = os.name > pathtocfg = os.path.dirname(sys.argv[0]) > configfileloc = os.path.abspath(pathtocfg) > os.chdir(configfileloc) > > to set the directory of all subsequent file lookups in a script. > > It worked underwindows because the shortcuts have a "Start In" > directory listing. > > I need something for Linux use that does not care about a symlink that > would be used to start the script. > > The above code finds the directory the symlink is in. > > I'm actually not suprised by this, it is what I expected, I just don't > understand how to fix it. > > How can I do something similar to this, but find the "real" dir? > Perhaps one of the other sys.argv arguments? > print(os.path.realpath(__file__)) HTH, Wayne
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