I had been doing this under windows: import os import sys
osname = os.name pathtocfg = os.path.dirname(sys.argv[0]) configfileloc = os.path.abspath(pathtocfg) os.chdir(configfileloc) to set the directory of all subsequent file lookups in a script. It worked underwindows because the shortcuts have a "Start In" directory listing. I need something for Linux use that does not care about a symlink that would be used to start the script. The above code finds the directory the symlink is in. I'm actually not suprised by this, it is what I expected, I just don't understand how to fix it. How can I do something similar to this, but find the "real" dir? Perhaps one of the other sys.argv arguments? Thanks for your help Rance _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
