> Date: Mon, 6 Sep 2010 21:45:17 +0200
> Subject: Re: [Tutor] exercise correct ??
> From: sander.swe...@gmail.com
> To: rwob...@hotmail.com
> CC: tutor@python.org
>
> On 6 September 2010 19:32, Roelof Wobben <rwob...@hotmail.com> wrote:
> > def index_of(val, seq, start=0):
> > """
> > >>> index_of(9, [1, 7, 11, 9, 10])
> > 3
> > >>> index_of(5, (1, 2, 4, 5, 6, 10, 5, 5))
> > 3
> > >>> index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)
> > 6
> > >>> index_of('y', 'happy birthday')
> > 4
> > >>> index_of('banana', ['apple', 'banana', 'cherry', 'date'])
> > 1
> > >>> index_of(5, [2, 3, 4])
> > -1
> > >>> index_of('b', ['apple', 'banana', 'cherry', 'date'])
> > -1
> > """
> > plek = 0
> > if type(seq) == type([]):
> > plek = seq.index(val)
> > elif type(seq) == type(()):
> > seq = list (seq)
> > plek = seq.index(val)
> > else :
> > plek = seq.find(val)
> > return plek
>
> Not sure if this is correct but why don't you check for the index
> attribute? It is part of both lists and strings. Also you can use
> try/except to catch a ValueError. My version below, but I dislike the
> list() usage...
>
> def index_of(val, seq, start=0):
> if hasattr(seq, 'index'):
> try:
> return seq.index(val, start)
> except ValueError:
> return -1
> else:
> try:
> return list(seq).index(val, start)
> except ValueError:
> return -1
>
> > File "C:\Users\wobben\workspace\oefeningen\src\test.py", line 70, in
> > __main__.index_of
> >
> > Failed example:
> >
> > index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)
> >
> > Expected:
> >
> > 6
> >
> > Got:
> >
> > 3
> >
> > But in that tuple 5 is on position 3.
> >
> > Is the exercise here wrong ?
>
> Looks like it, or it's a typo.
>
> Greets
> Sander
Hello Sander,
I agree that index is a part of string and list.
But not a part of a tuple.
As far as I know index is not a part of tuple so I have to convert it to a list
so I can use index.
Roelof
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