In [69]: l1=[(0,0)] * 4 In [70]: l1 Out[70]: [(0, 0), (0, 0), (0, 0), (0, 0)]
In [71]: l1[2][0] Out[71]: 0 In [72]: l1[2][0] = 3 --------------------------------------------------------------------------- TypeError Traceback (most recent call last) /home/bermanrl/<ipython console> in <module>() TypeError: 'tuple' object does not support item assignment First question, is the error referring to the assignment (3) or the index [2][0]. I think it is the index but if that is the case why does l1[2][0] produce the value assigned to that location and not the same error message. Second question, I do know that l1[2] = 3,1 will work. Does this mean I must know the value of both items in l1[2] before I change either value. I guess the correct question is how do I change or set the value of l1[0][1] when I specifically mean the second item of an element of a 2D array? I have read numerous explanations of this problem thanks to Google; but no real explanation of setting of one element of the pair without setting the second element of the pair as well. For whatever glimmers of clarity anyone can offer. I thank you. Robert
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