Solution 1:
>>> a=[2,3,1,4]
>>> b=a[:]
>>> a
[2, 3, 1, 4]
>>> b
[2, 3, 1, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4]
>>> b
[2, 3, 1, 4]
>>>
Solution 2:
>>> from copy import deepcopy
>>> a=[2,1,3,4]
>>> b=deepcopy(a)
>>> a
[2, 1, 3, 4]
>>> b
[2, 1, 3, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4]
>>> b
[2, 1, 3, 4]
>>>
HTH.
regards,
shantanoo
On 18-Sep-08, at 1:00 AM, Wayne Watson wrote:
I'm using Python 2.4 in Win XP. I was surprised to find the result
below.
>>> a =[4,2,5,8]
>>> b = a
>>> a.sort()
>>> a
[2, 4, 5, 8]
>>> b
[2, 4, 5, 8]
b no longer has the same value as it began. Apparently to prevent
sort from making it the same I have to resort to copying b into a
first? What is the proper way to retain a variable with the original
values of a?
--
Wayne Watson (Watson Adventures, Prop., Nevada City, CA)
(121.015 Deg. W, 39.262 Deg. N) GMT-8 hr std. time)
Obz Site: 39° 15' 7" N, 121° 2' 32" W, 2700 feet
"Though no one can go back and make a brand new start,
ANYONE can start from now and make a brand new end."
-- Anonymous
Web Page: <www.speckledwithstars.net/>
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http://mail.python.org/mailman/listinfo/tutor
