If you use sort(a), it will be ok. >>>a =[4,2,5,8]
>>>b=a >>> sort(a) : array([2, 4, 5, 8]) >>> b [4, 2, 5, 8] >>> a [4, 2, 5, 8] On Wed, Sep 17, 2008 at 12:30 PM, Wayne Watson <[EMAIL PROTECTED] > wrote: > I'm using Python 2.4 in Win XP. I was surprised to find the result below. > > >>> a =[4,2,5,8] > >>> b = a > >>> a.sort() > >>> a > [2, 4, 5, 8] > >>> b > [2, 4, 5, 8] > > b no longer has the same value as it began. Apparently to prevent sort from > making it the same I have to resort to copying b into a first? What is the > proper way to retain a variable with the original values of a? > -- > > Wayne Watson (Watson Adventures, Prop., Nevada City, CA) > > (121.015 Deg. W, 39.262 Deg. N) GMT-8 hr std. time) > Obz Site: 39° 15' 7" N, 121° 2' 32" W, 2700 feet > "Though no one can go back and make a brand new start, > ANYONE can start from now and make a brand new end." > -- Anonymous > > Web Page: <www.speckledwithstars.net/> > > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > >
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