Hello All,
I want trying to write a program that searches all the files (recursively)
under a given directory in the filesystem for phone
numbers in the form of (626) 674-5901 and and then outputting all phone
numbers found in a unique format 626-674
(If several numbers have the same office code, there should be only one line
of output for that office code.)
There are following requirments
1> Search for a pattern in all files in a directory
2> Outputing the result with a unique format ( (626) 674-5901 -> 626-674 )
3> if the result has new office code (which I am guessing first 3 digits --
626) -- add to new line
if the result has office code already in the list then append
~~~~~~~~
I have generated the regular expression for the pattern .... and have
tested it also....
\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}
>>> import re
>>> p = re.compile('\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}')
>>> p = re.compile('\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}')
>>> p
<_sre.SRE_Pattern object at 0x00C400B8>
>>> p
<_sre.SRE_Pattern object at 0x00C400B8>
>>> print p.match("")
None
>>> print p.match('(619) 223-1212')
<_sre.SRE_Match object at 0x00A3F678>
I need options to proceed after finding the match in the files.....
++++++++++++++++++++++++++++++++
I was thinking to find all filenames in the directory using something like
....
import os
path="C:\\somedirectory" # insert the path to the directory of interest
here
dirList=os.listdir(path)
for fname in dirList:
print fname
Am I thinking correct ???
~Thanks
Geo
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