Guess?!? wrote:
> Hello All,
>
> I want trying to write a program that searches all the files (
> recursively) under a given directory in the filesystem
> There are following requirments
> 1> Search for a pattern in all files in a directory
> 2> Outputing the result with a unique format ( (626) 674-5901 -> 626-674 )
> 3> if the result has new office code (which I am guessing first 3 digits
> -- 626) -- add to new line
> if the result has office code already in the list then append
>
>
> ~~~~~~~~
>
> I have generated the regular expression for the pattern .... and have
> tested it also....
>
> \([0-9]{3}\)\s[0-9]{3}-[0-9]{4}
>
>> >> import re
>> >> p = re.compile('\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}')
>> >> p = re.compile('\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}')
>> >> p
> <_sre.SRE_Pattern object at 0x00C400B8>
>> >> p
> <_sre.SRE_Pattern object at 0x00C400B8>
>> >> print p.match("")
> None
>> >> print p.match('(619) 223-1212')
> <_sre.SRE_Match object at 0x00A3F678>
>
> I need options to proceed after finding the match in the files.....
You can replace text using p.sub() (re.sub)
> ++++++++++++++++++++++++++++++++
> I was thinking to find all filenames in the directory using something
> like ....
>
> import os
> path="C:\\somedirectory" # insert the path to the directory of interest
> here
> dirList=os.listdir(path)
> for fname in dirList:
> print fname
>
> Am I thinking correct ???
Yes, did you try this code? It looks good to me.
To open the file you have to construct the full path, e.g.
fpath = os.path.join(path, fname)
f = open(fpath)
data = f.read()
f.close()
Then you can process the data with your regex and write it back out.
Kent
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