Kent Johnson wrote:
> Ricardo Aráoz wrote:
>> Yinghe Chen wrote:
>>> Hello gurus,
>>>
>>> I have a question, a function like below, it is implemented by me, :)
>>>
>>> def funcA(tarray):
>>> a = [2,3,4]
>>> if len(tarray) >=3:
>>> return a[0],a[1], a[2]
>>> elif len(tarray) == 2:
>>> return a[0],a[1], funcB(1)[0]
>>> elif len(tarray) == 1:
>>> return a[0], funcB(2)[0], funcB(2)[1]
>>> else:
>>> return funcB(3)[0], funcB(3)[1], funcB(3)[2]
>
>> def funcA(tArray) :
>> a = [2,3,4]
>> L = min(len(tArray), 3)
>> return tuple(i for n, i in enumerate(a) if n <
>> L)+tuple(funcB(len(a)-L))
>
> tuple(i for n, i in enumerate(a) if n < L) can be written
> tuple(a[:L])
Doh... Of course! Your code is much nicer.
>
> funcB(len(a)-L) does not do what the OP requested. For example if len(a)
> is 10, L will be 3 and you will call funcB(7).
>
Don't get it. The 3 is because the len(a) is 3, notice that a is hard
coded and not a parameter. If you change 'a' then you should change the
code accordingly. Anyway the confusion is the mixing of len(a) and 3 in
the same code, it should probably be either 3 or len(a) all along, but
that should be asked to the OP.
Let's say we decide to use len(a), then the code would end up like :
def funcA(tArray) :
a = [2,3,4]
L = min(len(tArray), len(a))
return tuple(a[:L]) + tuple(funcB(len(a) - L))
Too tired right now to check if it's ok.
Cheers.
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