"Yinghe Chen" <[EMAIL PROTECTED]> wrote
> def funcA(tarray):
> a = [2,3,4]
> if len(tarray) >=3:
> return a[0],a[1], a[2]
> elif len(tarray) == 2:
> return a[0],a[1], funcB(1)[0]
> elif len(tarray) == 1:
> return a[0], funcB(2)[0], funcB(2)[1]
> else:
> return funcB(3)[0], funcB(3)[1], funcB(3)[2]
>
>
> Is there a brief way to achieve it?
It looks fairly brief to me. There are a couple of things I
might consider changing.
def funcA(tArray, defs = (2,3,4), func = funcB):
if len(tArray) >= 3:
return defs
elif len(tArray) == 2:
return defs[0],defs[1], func(2)[1]
elif....
By making defs a tuple you can return it directly and by
making it a defaulted parameter you can change the
values if needed without changing the funcA code.
Similarly by making funcB a default parameter you
have the flexibility to change the algorithm used
without changing funcA. But because they are default
parameters you can still call it with just tArray as
an argument.
A small change but may significantly improve the
flexibility and possible reuse capability of funcA
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.freenetpages.co.uk/hp/alan.gauld
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