John Fouhy said unto the world upon 2005-10-24 22:18:
> On 25/10/05, Brian van den Broek <[EMAIL PROTECTED]> wrote:
>
>>To sort by the second item, try
>>
>> >>> def sort_by_second(sequence):
>> decorated = [(x[1], x) for x in sequence]
>> decorated.sort()
>> return [x[1] for x in decorated]
>
>
> With python2.4, you can use the key= argument to sort.
>
> eg:
>
>>>>arr = [('a', 5), ('b', 3), ('c', 7), ('d', 1), ('e', 2)]
>>>>arr.sort(key=lambda x: x[1])
>>>>arr
>
> [('d', 1), ('e', 2), ('b', 3), ('a', 5), ('c', 7)]
And that would be the better suggestion I predicted :-)
I also should have pointed out that I wrote
>>> noneless = [[x, y] for [x, y] in orig_list if not (x is None or y
is None)]
to be fully explicit. Better in real code (I think) would be
>>> noneless = [x for x in orig_list if not None in x]
>>> noneless
[['c', 'b'], ['a', 'g'], ['e', 'f']]
>>>
Best,
Brian vdB
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