John Fouhy wrote:
> On 25/10/05, Brian van den Broek <[EMAIL PROTECTED]> wrote:
>
>>To sort by the second item, try
>>
>> >>> def sort_by_second(sequence):
>> decorated = [(x[1], x) for x in sequence]
>> decorated.sort()
>> return [x[1] for x in decorated]
>
>
> With python2.4, you can use the key= argument to sort.
>
> eg:
>
>>>>arr = [('a', 5), ('b', 3), ('c', 7), ('d', 1), ('e', 2)]
>>>>arr.sort(key=lambda x: x[1])
and you can use operator.itemgetter() instead of a lambda - it is intended for
this usage:
>>> import operator
>>> arr = [('a', 5), ('b', 3), ('c', 7), ('d', 1), ('e', 2)]
>>> arr.sort(key=operator.itemgetter(1))
>>> arr
[('d', 1), ('e', 2), ('b', 3), ('a', 5), ('c', 7)]
Kent
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