Dear group,
I have two lists names x and seq.
I am trying to find element of x in element of seq. I
find them. However, I want to print element in seq
that contains element of x and also the next element
in seq.
So I tried this piece of code and get and error that
str and int cannot be concatenated
>>> for ele1 in x:
for ele2 in seq:
if ele1 in ele2:
print (seq[ele1+1])
Traceback (most recent call last):
File "<pyshell#173>", line 4, in -toplevel-
print (seq[ele1+1])
TypeError: cannot concatenate 'str' and 'int' objects
2. TRIAL TWO:
>>> for ele1 in x:
for ele2 in seq:
if ele2 in range(len(seq)):
if ele1 in ele2:
print seq[ele2+1]
This is taking forever and I am not getting an answer.
3. TRIAL 3:
I just asked to print the element in seq that matched
element 1 in X. It prints only that element, however
I want to print the next element too and I cannot get
it.
>>> for ele1 in x:
for ele2 in seq:
if ele1 in ele2:
print ele2
>probe:HG-U95Av2:31358_at:454:493;
Interrogation_Position=132; Antisense;
>probe:HG-U95Av2:31358_at:319:607;
Interrogation_Position=144; Antisense;
>>> len(x)
4504
>>> x[1:10]
['454:494', '319:607', '319:608', '322:289',
'322:290', '183:330', '183:329', '364:95', '364:96']
>>> len(seq)
398169
>>> seq[0:4]
['>probe:HG-U95Av2:1000_at:399:559;
Interrogation_Position=1367; Antisense;',
'TCTCCTTTGCTGAGGCCTCCAGCTT',
'>probe:HG-U95Av2:1000_at:544:185;
Interrogation_Position=1379; Antisense;',
'AGGCCTCCAGCTTCAGGCAGGCCAA']
>>> for ele1 in x:
for ele2 in seq:
if ele1 in ele2:
print ele2
>probe:HG-U95Av2:31358_at:454:493;
Interrogation_Position=132; Antisense;
>probe:HG-U95Av2:31358_at:319:607;
Interrogation_Position=144; Antisense;
How Do I WANT:
I want to print get an output like this:
>probe:HG-U95Av2:1000_at:399:559;
Interrogation_Position=1367; Antisense;'
TCTCCTTTGCTGAGGCCTCCAGCTT
>probe:HG-U95Av2:1000_at:544:185;
Interrogation_Position=1379; Antisense;
AGGCCTCCAGCTTCAGGCAGGCCAA
can any one please suggest what is going wrong in my
statements and how can I get it.
Thank you.
Kumar
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