Dear group, I have two lists names x and seq.
I am trying to find element of x in element of seq. I
find them. However, I want to print element in seq
that contains element of x and also the next element
in seq.
So I tried this piece of code and get and error that str and int cannot be concatenated
for ele1 in x:
for ele2 in seq: if ele1 in ele2: print (seq[ele1+1])
You are confusing the elements themselves with their indices. The problem here is that ele1 is a string - an element of x - not a number, which is what you need for an index.
for ele1 in x:
for ele2 in seq: if ele2 in range(len(seq)): if ele1 in ele2: print seq[ele2+1]
Now ele2 is a number, so 'if ele1 in ele2' is never true.
3. TRIAL 3:
I just asked to print the element in seq that matched
element 1 in X. It prints only that element, however
I want to print the next element too and I cannot get
it.
for ele1 in x:
for ele2 in seq: if ele1 in ele2: print ele2
The enumerate function is useful here. enumerate(seq) returns a sequence of (index, element) pairs. So you could write
for ele1 in x:
for index, ele2 in enumerate(seq):
if ele1 in ele2:
print ele2
print seq[index+1]Kent _______________________________________________ Tutor maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/tutor
