On Thu, Dec 6, 2012 at 5:55 PM, Jack Krupansky <j...@basetechnology.com> wrote: > I trust that you have the right answer, Mark, but maybe I'm just struggling > to parse this statement: "the remaining two machines do not constitute a > majority." > > If you start with 3 zk and lose one, you have an ensemble that does not > "constitute a majority".
I think you took that out of context. They were talking about losing 2 nodes in a 4 node cluster. "For example, with four machines ZooKeeper can only handle the failure of a single machine; if two machines fail, the remaining two machines do not constitute a majority." -Yonik http://lucidworks.com
