Maybe I am not clear, but I am not able to find anything on the net. Basically, if I had in my index millions of names starting with A* I would like to know how many distinct surnames are present in the resultset (similar to a distinct SQL query). I will attempt to have a look at the SOLR sources to try to see if this is possible to implement. Any hints where to look at would be great!
Thanks, Bruno 2009/2/3 Bruno Aranda <brunoara...@gmail.com> > But as far as I understand the total number of constraints is limited > (there is a default value), so I cannot know the total if I don't set the > facet.limit to a really big number and then the request takes a long time. I > was wondering if there was a way to get the total number (e.g. 100.000 > constraints) to show it to the user, and then paginate using facet.offset > and facet.limit until I reach that total. > Does this make sense? > > Thanks! > > Bruno > > 2009/2/3 Markus Jelsma - Buyways B.V. <mar...@buyways.nl> > > Hello, >> >> >> Searching for ?q=*:* with facetting turned on gives me the total number >> of available constraints, if that is what you mean. >> >> >> Cheers, >> >> >> >> On Tue, 2009-02-03 at 16:03 +0000, Bruno Aranda wrote: >> >> > Hi, >> > >> > I would like to know if is there a way to get the total number of >> different >> > facets returned by a faceted search? I see already that I can paginate >> > through the facets with the facet.offset and facet.limit, but there is a >> way >> > to know how many facets are found in total? >> > >> > For instance, >> > >> > Name Surname >> > >> > Peter Smith >> > John Smith >> > Anne Baker >> > Mary York >> > ... 1 million records more with 100.000 distinct surnames >> > >> > For instance, now I search for people with names starting with A, and I >> > retrieve 5000 results. I would like to know the distinct number of >> surnames >> > (facets) for the result set if possible, so I could show in my app >> something >> > like this: >> > >> > 5000 people found with 1440 distinct surnames. >> > >> > Any ideas? Is this possible to implement? Any pointers would be greatly >> > appreciated, >> > >> > Thanks! >> > >> > Bruno >> > >
