Hello,
Searching for ?q=*:* with facetting turned on gives me the total number of available constraints, if that is what you mean. Cheers, On Tue, 2009-02-03 at 16:03 +0000, Bruno Aranda wrote: > Hi, > > I would like to know if is there a way to get the total number of different > facets returned by a faceted search? I see already that I can paginate > through the facets with the facet.offset and facet.limit, but there is a way > to know how many facets are found in total? > > For instance, > > Name Surname > > Peter Smith > John Smith > Anne Baker > Mary York > ... 1 million records more with 100.000 distinct surnames > > For instance, now I search for people with names starting with A, and I > retrieve 5000 results. I would like to know the distinct number of surnames > (facets) for the result set if possible, so I could show in my app something > like this: > > 5000 people found with 1440 distinct surnames. > > Any ideas? Is this possible to implement? Any pointers would be greatly > appreciated, > > Thanks! > > Bruno
