Hello Jan,
If I get you right, you need to find every word either in parent or child
level, hence:
q=+({!edismax qf=$pflds v=$w1} {!parent ..}{!edismax qf=$cflds v=$w1})
+({!edismax qf=$pflds v=$w1} {!parent ..}{!edismax qf=$cflds
v=$w1})...&w1=foo&w2=bar
note that spaces and + matter much. This yields cross-matches, but you
probably don't bother about them.
On Sun, Mar 19, 2017 at 11:58 AM, Jan Nekuda <jan.nek...@gmail.com> wrote:
> Hi Michael,
> thank you for fast answer - I have tried it, but it's not exactly what I
> need. I hope that I understood it good - the problem is that if I will
> write foo bar and foo bar is not found in root entity then it returns
> nothing even if any field in children contains foo bar.
> I need to write foo bar and find all documents where foo bar exists in
> document A OR B OR C OR D even if in A will have FOO and in e.g C will be
> bar. But if I will write bar of chocolate then I need return nothing.
>
> my idea was to use
> edismax and filter query for each word:
> http://localhost:8983/solr/demo/select?q=*:*&fq={!parent
> which=type:root}foo*&fq={!parent
> which=typ:root}bar*&wt=json&indent=true&defType=edismax&
> qf=$allfields&stopwords=true&lowercaseOperators=true&allfieldscolor,
> first_country, power, name, country
>
> the problem is that I'm not able to find also parent documents in one
> condition with children.
>
> How I wrote I'm able solve it with another parent and then also doc A will
> be child and everything will work fine - but I would like to solve it
> better.
>
>
> Do you have or someone else another idea?:)
>
> Thanks
> Jan
>
>
> 2017-03-16 21:51 GMT+01:00 Mikhail Khludnev <m...@apache.org>:
>
> > Hello Jan,
> >
> > What if you combine child and parent dismaxes like below
> > q={!edismax qf=$parentfields}foo bar {!parent ..}{!dismax qf=$childfields
> > v=$childclauses}&childclauses=foo bar +type:child&parentfields=...&
> > parentfields=...
> >
> > On Thu, Mar 16, 2017 at 10:54 PM, Jan Nekuda <jan.nek...@gmail.com>
> wrote:
> >
> > > Hello Mikhail,
> > >
> > > thanks for fast answer. The problem is, that I want to have the dismax
> on
> > > child and parent together - to have the filter evaluated together.
> > >
> > > I need to have documents:
> > >
> > >
> > > path: car
> > >
> > > type:car
> > >
> > > color:red
> > >
> > > first_country: CZ
> > >
> > > name:seat
> > >
> > >
> > >
> > > path: car\engine
> > >
> > > type:engine
> > >
> > > power:63KW
> > >
> > >
> > >
> > > path: car\engine\manufacturer
> > >
> > > type:manufacturer
> > >
> > > name: xx
> > >
> > > country:PL
> > >
> > >
> > > path: car
> > >
> > > type:car
> > >
> > > color:green
> > >
> > > first_country: CZ
> > >
> > > name:skoda
> > >
> > >
> > >
> > > path: car\engine
> > >
> > > type:engine
> > >
> > > power:88KW
> > >
> > >
> > >
> > > path: car\engine\manufacturer
> > >
> > > type:manufacturer
> > >
> > > name: yy
> > >
> > > country:PL
> > >
> > >
> > > where car is parent document engine is its child a manufacturer is
> child
> > > of engine and the structure can be deep.
> > >
> > > I need to make a query with edismax over fields color, first_country,
> > > power, name, country over parent and all childern.
> > >
> > > when I ask then "seat 63 kw" i need to get seat car
> > >
> > > the same if I will write only "seat" or only "63kw" or only "xx"
> > >
> > > but if I will write "seat 88kw" i expect that i will get no result
> > >
> > > I need to return parents in which tree are all the words which I wrote
> to
> > > query.
> > >
> > > How I wrote before my solution was to split the query text and use
> q:*:*
> > > and for each /word/ in query make
> > >
> > > fq={!parent which=type:car}/word//
> > > /
> > >
> > > //and edismax with qf=color, first_country, power, name, country
> > >
> > > Thank you for your time:)
> > >
> > > Jan
> > >
> > >
> > > Dne 16.03.2017 v 20:00 Mikhail Khludnev napsal(a):
> > >
> > >
> > > Hello,
> > >>
> > >> It's hard to get into the problem. but you probably want to have
> dismax
> > on
> > >> child level:
> > >> q={!parent ...}{!edismax qf='childF1 childF2' v=$chq}&chq=foo bar
> > >> It's usually broken because child query might match parents which is
> not
> > >> allowed. Thus, it's probably can solved by adding +type:child into
> chq.
> > >> IIRC edismax supports lucene syntax.
> > >>
> > >> On Thu, Mar 16, 2017 at 4:47 PM, Jan Nekuda <jan.nek...@gmail.com>
> > wrote:
> > >>
> > >> Hi,
> > >>> I have a question for which I wasn't able to find a good solution.
> > >>> I have this structure of documents
> > >>>
> > >>> A
> > >>> |\
> > >>> | \
> > >>> B \
> > >>> \
> > >>> C
> > >>> \
> > >>> \
> > >>> \
> > >>> D
> > >>>
> > >>> Document type A has fields id_number, date_from, date_to
> > >>> Document type C has fields first_name, surname, birthdate
> > >>> Document type D AND B has fields street_name, house_number, city
> > >>>
> > >>>
> > >>> I want to find *all parents with block join and edismax*.
> > >>> The problem is that I have found that possible is find children by
> > >>> parent,
> > >>> or parent by children.
> > >>> *I want to find parent by values in parent and in children*. I want
> to
> > >>> use
> > >>> edismax with all fields from all documents (id_number, date_from,
> > >>> date_to,
> > >>> has fields first_name, surname, birthdate,street_name, house_number,
> > >>> city).
> > >>> I want to write *Hynek* AND *Brojova* AND 14 and I expect that it
> > returns
> > >>> document A because it found Hynek in surname, Brojova in street and
> 14
> > in
> > >>> house number.
> > >>> This is easy with {!parent which=type:A}
> > >>> the problem is, that I'm not able to find by condition 789 AND
> > *Brojova*
> > >>> where 789 is id_number from type A and Brojova is Street from D.
> > >>>
> > >>> In short I need to find all parents of tree (parent and childern) in
> > >>> which
> > >>> are matched all the word which i send to condition
> > >>>
> > >>>
> > >>> My only solution is to make root type X. Then A will be its child.
> > Then I
> > >>> can use {!parent which=type:X}.
> > >>> Than this will work:
> > >>>
> > >>> http://localhost:8983/solr/demo/select?q=*:*&fq={!parent
> > >>> which=type:X}brojova*&fq={!parent which=type:X}16&wt=json&
> > >>> indent=true&defType=edismax&qf=id_number date_from date_to has
> fields
> > >>> first_name surname birthdate street_name house_number
> > >>> city&stopwords=true&
> > >>> lowercaseOperators=true
> > >>>
> > >>>
> > >>> But I believe it can be solved much better.
> > >>>
> > >>> X
> > >>> |
> > >>> A
> > >>> |\
> > >>> | \
> > >>> B \
> > >>> \
> > >>> C
> > >>> \
> > >>> \
> > >>> \
> > >>> D
> > >>>
> > >>>
> > >>> Thanks for your help
> > >>> Jan
> > >>>
> > >>>
> > >>
> > >>
> > >
> > >
> > > ---
> > > Tato zpráva byla zkontrolována na viry programem Avast Antivirus.
> > > https://www.avast.com/antivirus
> > >
> >
> >
> >
> > --
> > Sincerely yours
> > Mikhail Khludnev
> >
>
--
Sincerely yours
Mikhail Khludnev
