Hello,
It's hard to get into the problem. but you probably want to have dismax on
child level:
q={!parent ...}{!edismax qf='childF1 childF2' v=$chq}&chq=foo bar
It's usually broken because child query might match parents which is not
allowed. Thus, it's probably can solved by adding +type:child into chq.
IIRC edismax supports lucene syntax.
On Thu, Mar 16, 2017 at 4:47 PM, Jan Nekuda <jan.nek...@gmail.com> wrote:
> Hi,
> I have a question for which I wasn't able to find a good solution.
> I have this structure of documents
>
> A
> |\
> | \
> B \
> \
> C
> \
> \
> \
> D
>
> Document type A has fields id_number, date_from, date_to
> Document type C has fields first_name, surname, birthdate
> Document type D AND B has fields street_name, house_number, city
>
>
> I want to find *all parents with block join and edismax*.
> The problem is that I have found that possible is find children by parent,
> or parent by children.
> *I want to find parent by values in parent and in children*. I want to use
> edismax with all fields from all documents (id_number, date_from, date_to,
> has fields first_name, surname, birthdate,street_name, house_number, city).
> I want to write *Hynek* AND *Brojova* AND 14 and I expect that it returns
> document A because it found Hynek in surname, Brojova in street and 14 in
> house number.
> This is easy with {!parent which=type:A}
> the problem is, that I'm not able to find by condition 789 AND *Brojova*
> where 789 is id_number from type A and Brojova is Street from D.
>
> In short I need to find all parents of tree (parent and childern) in which
> are matched all the word which i send to condition
>
>
> My only solution is to make root type X. Then A will be its child. Then I
> can use {!parent which=type:X}.
> Than this will work:
>
> http://localhost:8983/solr/demo/select?q=*:*&fq={!parent
> which=type:X}brojova*&fq={!parent which=type:X}16&wt=json&
> indent=true&defType=edismax&qf=id_number date_from date_to has fields
> first_name surname birthdate street_name house_number city&stopwords=true&
> lowercaseOperators=true
>
>
> But I believe it can be solved much better.
>
> X
> |
> A
> |\
> | \
> B \
> \
> C
> \
> \
> \
> D
>
>
> Thanks for your help
> Jan
>
--
Sincerely yours
Mikhail Khludnev
