On Tue, 14 Sep 2010 01:58:07 pm aenea...@priest.com wrote:
> if len(rgenre)>0:
> if len(rgenre)>2:
> rg1=rgenre[0]
> rg2=rgenre[1]
> rg3=rgenre[2]
> elif len(rgenre)==2:
> rg1=rgenre[0]
> rg2=rgenre[1]
>
On Tue, 14 Sep 2010 02:08:43 pm Vince Spicer wrote:
> Hey Tyler you can simplify this with a onliner.
>
> rg1, rg2, rg3 = rgenre + ["NA"]*(3-len(rgenre[:3]))
There's no real need to calculate the exact length that you want:
rg1, rg2, rg3 = (rgenre + ["NA"]*3)[:3]
For small numbers of items -- a
On Tue, Sep 14, 2010 at 2:46 PM, wrote:
> rgenre = re.split(r';', rf.info["genre"])
> KeyError: 'genre'
Use something like this:
if "genre" in rf.info:
rgenre = re.split(..., ...)
else:
# ... no genre
cheers
James
--
-- James Mills
--
-- "Problems are solved by method"
on't choke if you don't find any rgenres
> because rf.info["genre"] was empty". But maybe I need to define the "None"
> condition earlier?
>
> Basically a text file has this structure:
>
> High Noon
> Drama;Western # But this tag doesn't
A great flick
blah blah blah
# etc
# next review--all about the movie featured in the info tags
-----Original Message-
From: Vince Spicer
To: aenea...@priest.com
Cc: tutor@python.org
Sent: Mon, Sep 13, 2010 9:08 pm
Subject: Re: [Tutor] If/elif/else when a list is empty
On Mon, Sep 13, 201
On Tue, Sep 14, 2010 at 1:58 PM, wrote:
> rgenre = re.split(r';', rf.info["genre"]) # When movies have genre
First question. Why are you not using an XML parser (it looks like
your IMDB data files _are_ XML). e.g: elementree (in the standard
library).
> else len(rgenre)<1: # I was hoping thi
On Mon, Sep 13, 2010 at 9:58 PM, wrote:
> Hi,
>
> I'm parsing IMDB movie reviews (each movie is in its own text file). In my
> script, I'm trying to extract genre information. Movies have up to three
> categories of genres--but not all have a "genre" tag and that fact is making
> my script abort
