On Tue, 14 Sep 2010 02:08:43 pm Vince Spicer wrote: > Hey Tyler you can simplify this with a onliner. > > rg1, rg2, rg3 = rgenre + ["NA"]*(3-len(rgenre[:3]))
There's no real need to calculate the exact length that you want: rg1, rg2, rg3 = (rgenre + ["NA"]*3)[:3] For small numbers of items -- and three is pretty small -- that will be plenty efficient enough. If you had thousands of items, perhaps not, but for three, it's not worth the effort to try to be more clever. -- Steven D'Aprano _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
