wrote
How about this?
List = [1, 2, 3, 3, 3, 4, 5, 5]
for Item in list(set(List)):
print Item, List.count(Item)
Not bad and you don't need the convert back to list()
But it doesn't filter out those items which are unique
which the OP asked for.
So I guess it becomes
for item in set(L
.info>
*Cc:* tutor@python.org <mailto:tutor@python.org>
*Sent:* Friday, June 11, 2010 9:09 AM
*Subject:* Re: [Tutor] Looking for duplicates within a list [SOLVED]
Steven D'Aprano wrote:
On Sat, 12 Jun 2010 12:58:19 am Alan Gauld wrote:
Have you l
Hugo Arts wrote:
On 11 jun 2010, at 17:49, Steven D'Aprano wrote:
On Sat, 12 Jun 2010 12:58:19 am Alan Gauld wrote:
Have you looked at the count method of lists?
Something like:
counts = set(( item, mylist.count(item)) for item in mylist if
mylist.count(item) > 1)
That's a
> > counts =
> > set(( item, mylist.count(item)) for item in mylist if mylist.count(item) >
> Whee, this is great! I learned a lot today.
I should have added that although thats a one liner in code terms it does
involve iterating over the list twice - in count() - for each element. So it
How about this?
List = [1, 2, 3, 3, 3, 4, 5, 5]
for Item in list(set(List)):
print Item, List.count(Item)
- Original Message -
From: Ken G.
To: Steven D'Aprano
Cc: tutor@python.org
Sent: Friday, June 11, 2010 9:09 AM
Subject: Re: [Tutor] Looking for duplicates w
Steven D'Aprano wrote:
On Sat, 12 Jun 2010 12:58:19 am Alan Gauld wrote:
Have you looked at the count method of lists?
Something like:
counts = set(( item, mylist.count(item)) for item in mylist if
mylist.count(item) > 1)
That's a Shlemiel the Painter algorithm.
http://www.joelons
Dave Angel wrote:
Ken G. wrote:
I have been working on this problem for several days and I am not
making any progress. I have a group of 18 number, in ascending
order, within a list. They ranged from 1 to 39. Some numbers are
duplicated as much as three times or as few as none.
I started
Alan Gauld wrote:
"Ken G." wrote
In any event, if a number is listed more than once, I would like to
know how many times, such as 2 or 3 times. For example, '3' is
listed twice within a list.
Have you looked at the count method of lists?
Something like:
counts = set(( item, mylist.count
Jose Amoreira wrote:
On Friday, June 11, 2010 02:57:34 pm Ken G. wrote:
I have been working on this problem for several days and I am not making
any progress. I have a group of 18 number, in ascending order, within a
list. They ranged from 1 to 39. Some numbers are duplicated as much as
th
Sander Sweers wrote:
On 11 June 2010 15:57, Ken G. wrote:
In any event, if a number is listed more than once, I would like to know how
many times, such as 2 or 3 times. For example, '3' is listed twice within a
list.
If you do not have top keep the order of the number this will work.
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