<davidheise...@gmail.com> wrote
How about this?
List = [1, 2, 3, 3, 3, 4, 5, 5]
for Item in list(set(List)):
print Item, List.count(Item)
Not bad and you don't need the convert back to list()
But it doesn't filter out those items which are unique
which the OP asked for.
So I guess it becomes
for item in set(List):
n = List.count(item)
if n > 1:
print item, n
which is still pretty clear.
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
