i remember some scripts that test variables by the following way:
if [ "X$1" == "X" ]
obviously if $1 is null then the statement is true X==X, and if the
variable not null, the statement is false, so
if [ "X$1" == "X" ]
then
echo "arg is null"
else
echo "arg is $1"
fi
will work.
dbrett wro
Thanks to everybody for your help and explainations. I ended up with what
I needed and an explaination of how somethings work. I also have a
direction on where to learn more
thanks again
david
On Wed, 11 Dec 2002, Robert P. J. Day wrote:
> On Wed, 11 Dec 2002, dbrett wrote:
>
> > Now I am rea
On Wed, 11 Dec 2002, dbrett wrote:
> Now I am really confused!
>
> This works:
> #!/bin/bash
>
> if [ -z $1 ]; then
> echo ''
> echo "format is $0 'math equation'"
> echo "i.e. $0 (2+2)*3"
> echo ''
> exit
> fi
>
> echo $1 | /usr/bin/bc -l
assuming that
On Wed, 11 Dec 2002, dbrett wrote:
> Nope, unless I missed what you trying to get at.
>
> #!/bin/bash
>
> if [$1 == '']; then
> echo ''
> echo "format is $0 'math equation'"
> echo "i.e. $0 (2+2)*3"
> echo ''
> exit
> fi
>
> echo $1 | /usr/bin/bc -l 2>&1
; To: Robert P. J. Day
> > Cc: [EMAIL PROTECTED]
> > Subject: Re: minor bash script issue
> >
> >
> > I though your correction would work, but the output still gives me the
> > error message. I would really like to fix it, but will settle for not
> > s
On 11 Dec 2002, Bret Hughes wrote:
> format is ./bc.test.sh 'math equation'
> i.e. ./bc.test.sh (2+2)*3
>
> [bhughes@bretsony bhughes]$ bc.test.sh (2+2)*3
> bash: syntax error near unexpected token `(2+2)'
> [bhughes@bretsony bhughes]$
> [bhughes@bretsony bhughes]$ bc.test.sh '(2+2)*3'
> 12
by
Now I am really confused!
This works:
#!/bin/bash
if [ -z $1 ]; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo ''
exit
fi
echo $1 | /usr/bin/bc -l
If you notice the only change I made was go with the better test for a
blank v
> -Original Message-
> From: dbrett [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, December 11, 2002 2:29 PM
> To: Robert P. J. Day
> Cc: [EMAIL PROTECTED]
> Subject: Re: minor bash script issue
>
>
> I though your correction would work, but the output still g
I though your correction would work, but the output still gives me the
error message. I would really like to fix it, but will settle for not
seeing the error.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo
Nope, unless I missed what you trying to get at.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo ''
exit
fi
echo $1 | /usr/bin/bc -l 2>&1 /dev/null
Here is the output
./math "2 + 3 *( 5 - 3 )" <---
On Wed, 2002-12-11 at 12:05, dbrett wrote:
> I have a bash to math calucations. It works but also complains about the
> last line, even though it works.
>
> Any ideas how to fix the problem or at least not see the error message and
> still work.
>
> #!/bin/bash
>
> if [$1 == '']; then
>
On Wed, 11 Dec 2002, Francisco Neira wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> dbrett wrote:
> | I have a bash to math calucations. It works but also complains about the
> | last line, even though it works.
> |
> | Any ideas how to fix the problem or at least not see the error
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
dbrett wrote:
| I have a bash to math calucations. It works but also complains about the
| last line, even though it works.
|
| Any ideas how to fix the problem or at least not see the error message and
| still work.
|
| #!/bin/bash
|
| if [$1 == ''];
I have a bash to math calucations. It works but also complains about the
last line, even though it works.
Any ideas how to fix the problem or at least not see the error message and
still work.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
e
14 matches
Mail list logo
