It didn't work for me, but changing it to if [ -z $1 ]; then
did, the spaces are required. david On Wed, 11 Dec 2002, James Francis wrote: > > -----Original Message----- > > From: dbrett [mailto:[EMAIL PROTECTED]] > > Sent: Wednesday, December 11, 2002 2:29 PM > > To: Robert P. J. Day > > Cc: [EMAIL PROTECTED] > > Subject: Re: minor bash script issue > > > > > > I though your correction would work, but the output still gives me the > > error message. I would really like to fix it, but will settle for not > > seeing the error. > > > > > > #!/bin/bash > > > > if [$1 == '']; then > > echo '' > > echo "format is $0 'math equation'" > > echo "i.e. $0 (2+2)*3" > > echo '' > > exit > > fi > > > > echo $1 | /usr/bin/bc -l 2>/dev/null > > > > david > Change your test line to: > if test "$1" == ''; then > instead of using the [ ] primitives and you will be golden. > The [ ] syntax of the test command is having trouble because > of the parenthesis in your expression. > > JMF > > > > -- > redhat-list mailing list > unsubscribe mailto:[EMAIL PROTECTED]?subject=unsubscribe > https://listman.redhat.com/mailman/listinfo/redhat-list > -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED]?subject=unsubscribe https://listman.redhat.com/mailman/listinfo/redhat-list
