Dear R and hydrological/environmental community,
A major release of hydroPSO is now available on CRAN. This new release:
-) implements the Standard Particle Swarm 2011 (SPSO-2011)
-) is parallel-capable, to alleviate the computational burden of
complex models with "long" execution time
-) has an
Hi AK
Regarding the missing values, I would like to find out the patterns of
missing values in my data set. I know the overall values for each variable.
using
colSums(is.na(df))
but what I wanted is to find out the percentages
with each level of the variable with my datas
Dear colleagues,
This is to inform you that Version 1.0 of the R package royston has been
released on CRAN. This package has a function to generate the Shapiro-Wilk's W
statistic needed to feed the Royston's test for multivariate normality. It was
taken from the Fortran Algorithm AS R94 (Roysto
Dear R users,
I just join this forum a few minutes ago. My friend recommend this forum to me.
I have data in excel csv. My problem is I would like to extract some number,
for example as highlighted below;
Year Ending Maximum Value (Rain mm)
Gap from 19710509 09 to 19710607 08000
I am trying to build R-patched from source on a (newly installed)
Fedora 17 system on a new laptop.
When I do the usual ./configure the procedure comes to a halt
with the error message:
configure: error: --with-x=yes (default) and X11 headers/libs are not
available
But X11 is installed, and
Hi,
I'd like to merge mutliple dataframes from a list of dataframes by some common
columns. The approach for simply merging 2 dataframes is working with:
merge(df1,df2,by=c("col1","col2","col3"),all=TRUE)
For mutliple dataframes in a list I try to use the merge_all command
from the package resha
Le vendredi 11 janvier 2013 à 14:50 +1300, Rolf Turner a écrit :
> Some while ago I posted a problem on this list concerning a failure of
> R CMD check on one of my packages that resulted from LaTeX being
> unable to find the "inconsolata" font. This was under the Ubuntu OS.
>
> This was solved,
On 13-01-10 4:54 PM, michele caseposta wrote:
Hi everybody,
thanks for the replies.
I might have not explained the problem completely.
Duncan Mackay:
Yes, I am already having a master file and separate Rnw files.
Duncan Murdock:
I am using patchDVI in the TexShop Sweave engine.
Sync works flawles
Hi
No HTML. No highlighting.
if you want some data from object use extraction operator
?"["
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of shairul samat
> Sent: Friday, January 11, 2013 10:19 AM
> To: r-help@r-proje
Dear all,
i would like to count the number of times where I have combined occurrences of
the categories of 2 variables.
For instance, in the dataframe below, i would like to know how many times each
author (au1, au2, au3 represent the first, second, third author) is associated
with each of t
Hi
structure of your data frame is not suitable for this task.
library(reshape)
tutu.m<-melt(tutu, "nam")
table(tutu.m$nam, tutu.m$value)
art deb joy mar seb lio nem tat
da 2 3 1 4 1 1 0 0
fr 2 2 2 3 0 1 1 1
ya 1 2 1 0 0 1 1 0
Rega
Hello,
Maybe you can try something like that:
count.au1 <- tapply(tutu$au1, tutu$nam, table)
count.au2 <- tapply(tutu$au2, tutu$nam, table)
count.au3 <- tapply(tutu$au3, tutu$nam, table)
HTH,
Pascal
Le 11/01/2013 19:54, Biau David a écrit :
Dear all,
i would like to count the number of times
Hi, I have a dataframe with n columns, but I am only looking at five of them.
And lots of rows, over 700.
So I would like to find frequencies for each of the numeric columns (variables)
using the table function. However, is there a fast way to produce a frequency
table where the 5 rows represen
Le vendredi 11 janvier 2013 à 22:45 +1300, Rolf Turner a écrit :
> I am trying to build R-patched from source on a (newly installed)
> Fedora 17 system on a new laptop.
>
> When I do the usual ./configure the procedure comes to a halt
> with the error message:
>
> > configure: error: --with-x=yes
On 11/01/2013 11:28, Milan Bouchet-Valat wrote:
Le vendredi 11 janvier 2013 à 22:45 +1300, Rolf Turner a écrit :
I am trying to build R-patched from source on a (newly installed)
Fedora 17 system on a new laptop.
When I do the usual ./configure the procedure comes to a halt
with the error messa
On 11/01/2013 01:50, Rolf Turner wrote:
Some while ago I posted a problem on this list concerning a failure of
R CMD check on one of my packages that resulted from LaTeX being
unable to find the "inconsolata" font. This was under the Ubuntu OS.
This was solved, thanks to advice I got from this
Hello,
To "solve" the problem you can use all.x and all.y but I think there are
other problems with merge_all, in the example below it doesn't include
df2$Y in the result df.
df1 <- data.frame(col1=1:10, col2=11:20, col3=21:30, X = rnorm(10))
df2 <- data.frame(col1=1:10, col2=11:20, col3=21:
Hi Rui,
thank you so far for your answer...
...as i found these other problems also myself, I decided to go
for a looping apporach with the base merge command and always
add a new dataframe to the old one (growing dataframe).
/johannes
On Fri, Jan 11, 2013 at 1:26 PM, Rui Barradas wrote:
> Hell
Hi,
I would like to split dataframe based on one colum and want
to connect the two dataframes by rows (like rbind). Here a small example:
# The orgininal dataframe
df1 <- data.frame(col1 = c("A","A","B","B"),col2 = c(1:4), col3 = c(1:4))
# The datafame how it could look like
df2 <- data.frame(A.
Does something like this do what you want? It returns a list of tables
md <- data.frame((matrix(sample(1:5, 100, replace = TRUE),nrow= 10)))
str(md)
apply(md, 2, table)
John Kane
Kingston ON Canada
> -Original Message-
> From: p.mulong...@namibia.pharmaccess.org
> Sent: Fri, 11 J
Hi, welcome to the R-help list
This help list does not accept html coded messages and so nothing meaningful
seems to have come through.
If you aready have the data loaded into R please supply some sample data
The easiest way to supply data is to use the dput() function. Example with
your
> PS: Just a related side-question: Why is merge_all not included in the
> "newer" package reshape2 as this is considered to be a reboot of the
> reshape package?
Because it doesn't work very well, as you've discovered.
There's an equivalent join_all in plyr.
Hadley
--
Chief Scientist, RStudio
On 2013-01-11 01:50, Rolf Turner wrote:
>
> Some while ago I posted a problem on this list concerning a failure of
> R CMD check on one of my packages that resulted from LaTeX being
> unable to find the "inconsolata" font. This was under the Ubuntu OS.
>
> This was solved, thanks to advice I got f
> Prof Brian Ripley
> on Fri, 11 Jan 2013 11:49:26 + writes:
> On 11/01/2013 01:50, Rolf Turner wrote:
>>
>> Some while ago I posted a problem on this list concerning a failure of
>> R CMD check on one of my packages that resulted from LaTeX being
>> unable to
Hi,
When using the aggregate function to aggregate a data.frame by one or more
grouping variables I often have the problem, that I want the mean for some
numeric variables but the unique value for factor variables.
So for example in this data-frame:
data <- data.frame(x = rnorm(10,1,2), group
Hi Johannes,
Your example is tricky because the original df1 does not contain id
columns that identify each cell in df2. If you want to use the
reshape2 package for this I think you have to add a second id
variable:
df1 <- data.frame(col1 = c("A","A","B","B"),col2 = c(1:4), col3 = c(1:4))
librar
Please see in line.
On Fri, Jan 11, 2013 at 10:07 AM, Martin Batholdy
wrote:
> Hi,
>
> When using the aggregate function to aggregate a data.frame by one or more
> grouping variables I often have the problem, that I want the mean for some
> numeric variables but the unique value for factor vari
On Jan 11, 2013, at 2:54 AM, Biau David wrote:
Dear all,
i would like to count the number of times where I have combined
occurrences of the categories of 2 variables.
For instance, in the dataframe below, i would like to know how many
times each author (au1, au2, au3 represent the first,
On Fri, Jan 11, 2013 at 6:46 AM, Johannes Radinger <
johannesradin...@gmail.com> wrote:
> I would like to split dataframe based on one colum and want
> to connect the two dataframes by rows (like rbind). Here a small example:
>
> # The orgininal dataframe
> df1 <- data.frame(col1 = c("A","A","B","
R 2.15.2 installed as a regular user on Windows 7.
Three issues:
1. There is a start menu item for "R 2.15.2 Help" that opens a local web
page. If I click on packages, then base, then abbreviate I get
"Firefox can't find the file at
/C:/Users/rdboylan/Documents/R/R-2.15.2/library/base/html/ab
On Jan 11, 2013, at 9:47 AM, arun wrote:
HI David,
I get different results with dcast()
library(reshape2)
dcast(melt(tutu,"nam"),nam~value,length)
# nam art deb joy mar seb lio nem tat
#1 da 2 3 1 4 1 1 0 0
#2 fr 2 2 2 3 0 1 1 1
#3 ya 1 2 1 0 0
Dear useRs,
I have a very basic question. I have a distance matrix and i skipped the upper
part of it deliberately. The distance matrix is 1000*1000. Then i used "min"
command to extract the lowest value from that matrix. Now i want to know what
is the location of that lowest element? More pre
On 11-01-2013, at 18:55, eliza botto wrote:
>
> Dear useRs,
> I have a very basic question. I have a distance matrix and i skipped the
> upper part of it deliberately. The distance matrix is 1000*1000. Then i used
> "min" command to extract the lowest value from that matrix. Now i want to
>
On Fri, Jan 11, 2013 at 11:55 AM, eliza botto wrote:
>
> Dear useRs,
> I have a very basic question. I have a distance matrix and i skipped the
> upper part of it deliberately. The distance matrix is 1000*1000. Then i
> used "min" command to extract the lowest value from that matrix. Now i want
>
On 11/01/2013 12:49 PM, Ross Boylan wrote:
R 2.15.2 installed as a regular user on Windows 7.
Three issues:
1. There is a start menu item for "R 2.15.2 Help" that opens a local web
page. If I click on packages, then base, then abbreviate I get
"Firefox can't find the file at
/C:/Users/rdboylan
On Jan 11, 2013, at 9:55 AM, eliza botto wrote:
Dear useRs,
I have a very basic question. I have a distance matrix and i skipped
the upper part of it deliberately.
I have no idea what htat means. Code is always helpful in resolving
ambiguities.
The distance matrix is 1000*1000. Then i
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst <-
list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[1]][1] 4 5 6[[2]][[2]][1]
4 5 6[[2]][[3]][1]
Dear R-users,
I am trying to understand how the 'segmented'-package works to determine
breakpoints and slopes of regression lines in broken-line regression models.
However, I am not able to repeat the example on the "plant"-dataset,
which was reported in the accompanying paper of the package. (V
Hello, I have 50 raters and 180 cases which are rated as malignant, probably
malignant, probably benign, and benign. I want to compare all the raters but
I want a weighted kappa to penalize differences between malignant and benign
more than differences between malignant and probably malign
HI,
You could try this:
library(reshape2)
dcast(melt(tutu,"nam"),nam~value,length)
# nam art deb joy mar seb lio nem tat
#1 da 2 3 1 4 1 1 0 0
#2 fr 2 2 2 3 0 1 1 1
#3 ya 1 2 1 0 0 1 1 0
A.K.
- Original Message -
From: Biau David
To
Dear Users,
I have the following text plotted inside a graphic:
text(16200, 2.8*0.97, expression(NH[3]==0.33-1.1 %*% 10^-5 %*% day),
adj=c(1,1))
I need to include square brackets in the expression around the ammonia to have
it plotted like that: [NO3-]. I tried instinctively to use %[% to plo
Ah! Very nice. Thank you, Arun!
--
View this message in context:
http://r.789695.n4.nabble.com/Learning-to-speak-R-simple-data-processing-tp4655194p4655237.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
Hi,
Hope this is what you meant.
#data1
aggregate(.~group+gender,data=data1,mean)
# group gender x
#1 2 f 1.750686
#2 1 m -1.074343
A.K.
- Original Message -
From: Martin Batholdy
To: "r-help@r-project.org"
Cc:
Sent: Friday, January 11, 2013 10:07 AM
Subje
HI David,
I get different results with dcast()
library(reshape2)
dcast(melt(tutu,"nam"),nam~value,length)
# nam art deb joy mar seb lio nem tat
#1 da 2 3 1 4 1 1 0 0
#2 fr 2 2 2 3 0 1 1 1
#3 ya 1 2 1 0 0 1 1 0
tutus <- data.frame(nam=tutu$na
Hi,
May be I misunderstood ur question.
You could do this:
res<-aggregate(.~group,data=data1,mean)
res$gender<-data1$gender[match(res$gender,as.numeric(data1$gender))]
res
# group x gender
#1 1 -1.074343 m
#2 2 1.750686 f
A.K.
- Original Message -
From: Mar
HI,
May be this also works for you:
do.call(cbind,by(df1[,-1],df1[,1],function(x) x))
# A.col2 A.col3 B.col2 B.col3
#1 1 1 3 3
#2 2 2 4 4
A.K.
- Original Message -
From: Johannes Radinger
To: r-help@r-project.org
Cc:
Sent: Friday, January 11,
Hi,
To get the missing values, you could use:
set.seed(15)
dat1<-data.frame(Gender=rep(c("M","F"),each=10),
V1=sample(c(1:20,NA),20,replace=TRUE), V2=sample(c(20:30,NA),20,replace=TRUE))
library(reshape2)
dcast(melt(dat1,id="Gender"),Gender~variable,function(x) sum(is.na(x)))
# Gender V1 V2
#1
1. Minimum Mean Square Estimation (for Multi-Dimensional Linear
Regression)
2. Two-Sample Kolmogorov-Smirnov Tests
3. Empirical ANOVA Methods
All this to be done on empirical data.
I am new to the R world, any help would be appreciated.
Thank You,
Bill Gilliland
Lead Senso
Big Dipper TV Presents Gimmie da Mic "Queen City Cypher"
For Registration & More info visit www.bigdippertv.com
Big Dipper Entertainment TV sent this email to r-help@R-project.org
Questions? Contact bigdippe...@gmail.com or Big Dipper Entertainment TV, c/o
You might be better off using the knitr package which has options for
whether to evaluate code or not (or which pieces of code to evaluate). If
you use this in Rstudio then you can knit directly to html from a variety
of input formats. Otherwise you can use the external program pandoc to
convert
Thanks to Duncan for all his help. I have one tip to pass on.
On 1/11/2013 10:34 AM, Duncan Murdoch wrote:
On 11/01/2013 12:49 PM, Ross Boylan wrote:
R 2.15.2 installed as a regular user on Windows 7.
Three issues:
1. There is a start menu item for "R 2.15.2 Help" that opens a local web
page.
The apply function takes another function as the argument to be applied to
each row (or column) of the matrix. You can use an existing function like
you did with 'max' and in this case there is an existing function called
'which.max' that does exactly what you want. If there is not an existing
fu
Read "An Introduction to R" before posting further, please. You need
to make at least some minimal effort to learn R first.
-- Bert
On Fri, Jan 11, 2013 at 10:20 AM, Gilliland, Bill wrote:
> 1. Minimum Mean Square Estimation (for Multi-Dimensional Linear
> Regression)
>
> 2. Two-Sam
... and, I should have added, to learn how to search within R.
?help
?help.search
?help.start
?RSiteSearch
There are also numerous other search engines that can be useful, such
as RSeek.or. But google generally works well, too.
-- Bert
On Fri, Jan 11, 2013 at 10:20 AM, Gilliland, Bill wrote:
>
lapply(lst, function(x) return(x[[2]]))
On Fri, Jan 11, 2013 at 6:40 AM, Bjoern Helm wrote:
> Dear R users,I have a list of equally structured lists, how can I access e.g.
> all 2nd compontents in those sub-lists?An example:lst <-
> list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1]
Hello
Let's say I have a multivariate zoo timeseries (synchronised automatic
loggers at different places):
library(zoo)
library(lattice)
library(latticeExtra)
x<-zoo(data.frame(a=rnorm(100), c=rnorm(100), b=rnorm(100)),
seq(from=as.Date("2010-01-01"), by="day", length.out=100))
and a dataframe
On Jan 11, 2013, at 10:20 AM, Gilliland, Bill wrote:
> 1. Minimum Mean Square Estimation (for Multi-Dimensional Linear
> Regression)
?lm
>
> 2. Two-Sample Kolmogorov-Smirnov Tests
?ks.test
>
> 3. Empirical ANOVA Methods
?lm
>
> All this to be done on empirical data.
As
str(x) ; str(y) reveals
#zoo series ...
# ..$ : chr [1:3] "a" "c" "b" ## HERE
# Index: Date[1:100], format: "2010-01-01" "2010-01-02" "2010-01-03"
"2010-01-04" ...
#'data.frame':99 obs. of 3 variables:
# $ ID : Factor w/ 3 levels "a","b","c": ## HERE
# ..
On Fri, Jan 11, 2013 at 12:50 PM, array chip wrote:
> Hi,
>
> I have some protein array data, each array in a separate text file. So I
> read them in and try to combine them into a single data frame by using
> merge(). see code below (If you download the attached data files into a
> specific fold
Hi James,
I am trying to combine 11 data frames by column, not by row. My original
message has 11 data text files attached, did they go through so you can try my
codes?
Thanks
John
From: J Toll
Cc: "r-help@r-project.org"
Sent: Friday, January 11, 2013
Hi Dennis,
Actually, I am trying to combine them by COLUMN, so
that's why I am using merge(). The first loop was to simply read these
protein data into R as 11 data frames, each data frame is 165 x 2. Then I
use merge() to combine these data frames into 1 big data frame by
column with these in
I just figured out the reason was the column (the 1st column in each data frame
"gene.name") by which to merge each data frame has no unique values, some
values were repeated, so when merging, the data frame gets bigger and bigger
exponentially.
Sorry to bother all.
John
___
If you have a dist object (created by dist()) or if you used lower.tri(x) to
extract the lower triangle of the matrix, which() will not work since the
matrix is now stored as a numeric vector with n(n-1)/2 elements where n is
the number of rows/columns. In that case you must compute the original
ro
On Jan 11, 2013, at 1:51 PM, David L Carlson wrote:
> If you have a dist object (created by dist()) or if you used lower.tri(x) to
> extract the lower triangle of the matrix, which() will not work since the
> matrix is now stored as a numeric vector with n(n-1)/2 elements where n is
> the number
If you really have a matrix to begin with, yes. But if you generated it from
dist() or its relations, you would have to convert it to a matrix (roughly
doubling the memory needed). The various hierarchical cluster functions
usually want a dist object.
> dm <- dist(x, diag=TRUE, upper=TRUE)
> str(d
Dear All,
Does anyone know whether there is a R package existed for dimension
reduction (manifold learning) methods, especially like Laplacian Eigenmaps?
Thanks a lot!
Best,
Jieyue
[[alternative HTML version deleted]]
__
R-help@r-project.org
Thank you for your response. However, I don't think the examples on that page
relate to my problem. The power function I am using is different than the ones
in the pwr package because I am working on the power for survival data with
competing risks. I tried to emulate the examples in the link yo
Dear all,thanyou so very much.
elisa
> From: dcarl...@tamu.edu
> To: dwinsem...@comcast.net
> CC: eliza_bo...@hotmail.com; r-help@r-project.org
> Subject: RE: [R] locating element in distance matrix
> Date: Fri, 11 Jan 2013 16:41:13 -0600
>
> If you really have a matrix to begin with, yes. But i
Dear all,
I have a data frame where there are three variables: values, experiment,
composite.
Values are numerical values. There are 10 levels for the experiment. Within
each level of experiment,
there are 17 levels of composite.
I want to find mean for each combination of levels of the experi
On 01/12/2013 12:40 AM, Bjoern Helm wrote:
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst <-
list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[
Hello,
Try the following.
# make up some data
dat <- data.frame(values = rnorm(100), experiment = sample(10, 100,
TRUE), composite = sample(17, 100, TRUE))
aggregate(values ~ experiment + composite, data = dat, FUN = mean)
Hope this helps,
Rui Barradas
Em 11-01-2013 23:26, li li escreveu:
Hi,
thank you. I just came up with
lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
but your solution is much more elegant. Although I don't completely understand:
if lst is the argument of function x[[2]] this should be iterpreted as
lst[[2]]. Where am I wrong?
Björn
Am 11.01.20
Hello,
Does an R package exist for communication with instruments using GPIB
(IEEE 488) protocol?
Something similar exists in python for control of instruments over
GPIB, RS232, or USB buses (http://pyvisa.sourceforge.net/)
Thanks,
Marko
__
R-help@r-p
Hello
I want to draw a plot using the code below.
Further, I want to add labels (White, Yellow, Red) to x-axis.
Please kindly advise how to add the categorical labels, by modifying the
code.
Thank you.
Elaine
Code
dataN <-read.csv("H:/skin_color.csv",header=T, row.names=1)
dim(dataN)
Hello
I have a data composing three columns: body weight, body length, and sex.
I want to draw a box plot, X-axis for body weight, Y-axis for body length.
In the boxplot,
I want to compare the body length between two sexes of three groups of body
weight: <50, 51-100, >101 kg.
(For instance
Can you please explain the syntax?
What I am trying to achieve is something of the sort( below is just an
example):
eg: Males hv 32% missing data as compared to 48% missing data amongst
females. 60% missing data from primary educated compared to 5% in those
completed uni.etc.
Thanks a lot
On Sa
On Jan 11, 2013, at 3:26 PM, Bjoern Helm wrote:
> Hi,
> thank you. I just came up with
>
> lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
>
>
> but your solution is much more elegant. Although I don't completely
> understand: if lst is the argument of function x[[2]] this should
On 01/12/2013 12:41 AM, Prof Brian Ripley wrote:
On 11/01/2013 11:28, Milan Bouchet-Valat wrote:
Le vendredi 11 janvier 2013 à 22:45 +1300, Rolf Turner a écrit :
I am trying to build R-patched from source on a (newly installed)
Fedora 17 system on a new laptop.
When I do the usual ./configure
Thanks to everyone who responded to my cri de coeur.
For the record, the solution to the problem was (in short) to do:
sudo yum install texlive
sudo yum install tex-inconsolata.noarch
sudo yum install texlive-collection-fontsrecommended
the last bit being the part that got me over one last hum
Hello,
I am using lattice to produce xyplot.
I want to change the font size of axis-X label.
Please kindly advise how to write the code.
Thank you.
For changing the font size of axis-X title
it would be
xlab=list("Diet of Breeding Ground", cex = 1.4)
Elaine
[[alternative HTML versio
Hello
I ran the code below but it said:
no object "'panel.xyplot.intermediate.hh'"
Please kindly advise how to modify the code.
thank you.
(It works with panel.bwplot.intermediate.hh)
Elaine
code
library(HH)
# data input
dataN <-read.csv("H:/R_data/Mig_bird_586.csv",header=T, row.names
Tried to do a plot just now and got an error:
Error in text.default(2, 6, main, cex = cex) :
X11 font -adobe-helvetica-%s-%s-*-*-%d-*-*-*-*-*-*-*, face 1 at size
16 could not be loaded
This is reproducible (in my current environment) via:
par(mfrow=c(2,2))
plot(1:10)
text(2,6,"Oh, hell!",c
Hello
I want to draw a xyplot.
Its dots will have three colors: red for meat, green for vegetable, and
blue for both.
I used the code below but could not make the dot in the same group show the
same color.
Please kindly advise how to modify it.
Thank you.
code
library (lattice)
diet.code <- c(
On Jan 11, 2013, at 8:38 PM, Elaine Kuo wrote:
Hello
I want to draw a xyplot.
Its dots will have three colors: red for meat, green for vegetable,
and
blue for both.
I used the code below but could not make the dot in the same group
show the
same color.
Please kindly advise how to modify
Hi
I do want percentages of the categories inthe whole data set. But, I am a
bit unclear about this syntax. Can you explain please. This is the error
message I got with your script?
Error: could not find function "Copy.of.BP_2". Not sure what, because
the data frame was already loaded.
Also
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