Dear all,
Here is one more way to go though using rep() and then matrix():
> rows <- 1:3
> matrix(rep(rows,5),ncol=5)
[,1] [,2] [,3] [,4] [,5]
[1,]11111
[2,]22222
[3,]33333
HTH,
Jorge
On Tue, Feb 24, 2009 at 1:43 PM, Gabor Grothe
Suppose we want 3 rows and the ith row should have 5 columns of i.
Create a list whose ith component is the ith row and rbind them:
> rows <- 1:3
> do.call(rbind, lapply(rows, rep, 5))
[,1] [,2] [,3] [,4] [,5]
[1,]11111
[2,]22222
[3,]333
If you know the final size that your matrix will be, it is better to
preallocate the matrix, then insert the rows into the matrix:
mymat <- matrix( nrow=100, ncol=10 )
for( i in 1:100 ){
mymat[i, ] <- rnorm(10)
}
Even better than this is to use replicate or sapply if you can, they will t
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