Suppose we want 3 rows and the ith row should have 5 columns of i.
Create a list whose ith component is the ith row and rbind them:
> rows <- 1:3
> do.call(rbind, lapply(rows, rep, 5))
[,1] [,2] [,3] [,4] [,5]
[1,] 1 1 1 1 1
[2,] 2 2 2 2 2
[3,] 3 3 3 3 3
On Tue, Feb 24, 2009 at 1:01 PM, Alexy Khrabrov <delivera...@gmail.com> wrote:
> I'm growing a large dataframe by composing new rows and then doing
>
> row <- compute.new.row.somehow(...)
> d <- rbind(d,row)
>
> Is this a fast/preferred way?
> Cheers,
> Alexy
>
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