So this works... Thanks. My mistake was leaving out seq_len()
for (i in seq_len(nrow(Volumes))){
plot(as.numeric(deltas[i,]))
Sys.sleep(0.5); }
Ken Spriggs wrote:
>
> I appreciate the response but if this is what you have in mind I didn't
> get anything different.
> Any ideas why?
>
> f
The goal is to look at an evolution of a process over 400 steps. I don't
really need to page back and forth so much as I'd like to just watch it like
a flip book.
jholtman wrote:
>
> Write it out to a PDF file and you can view at your leasure. On WIndows
> you
> have the option of paging b
I appreciate the response but if this is what you have in mind I didn't get
anything different.
Any ideas why?
for (i in nrow(Volumes)){
plot(as.numeric(deltas[i,]))
Sys.sleep(0.5); }
Thanks
Jan T. Kim wrote:
>
> On Mon, Jun 09, 2008 at 02:02:01PM -0700, Ken Spriggs wrote:
>>
>> Hello,
>>
On Mon, Jun 09, 2008 at 02:02:01PM -0700, Ken Spriggs wrote:
>
> Hello,
>
> This code works fine but is so fast I can't see anything but the last plot.
>
> for (i in nrow(X)){
> plot(as.numeric(d[i,])) }
>
> I'd like to view a plot every 500 milliseconds, nrow(X) = 400. How?
Adding the
Write it out to a PDF file and you can view at your leasure. On WIndows you
have the option of paging back and forth between the plots.
On Mon, Jun 9, 2008 at 5:02 PM, Ken Spriggs <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
> This code works fine but is so fast I can't see anything but the last plot
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